How to reverse a number in C++?

Write a C++ program to reverse digits of a number 

Reverse number:-
Input=7890
Output=0987

Algorithm:-

Input=number
reverse_number=0;
while loop number > 0

(a)multiply reverse_number by 10 and add remainder    of number divide by 10 to reverse_number
   reverse_number= reverse_number*10+number%10;

(b)divide number by 10
   number=number/10;

print reverse_number.

Approach to solve:-

Input:num=7890

rev_num=0

rev_num=rev_num*10+num%10=0

num=num/10=789

rev_num=rev_num*10+num%10=09

num=num/10=78

rev_num=rev_num*10+num%10=098

num=num/10=7

rev_num=rev_num*10+num%10=0987

num=num/10=0

Program:-

#include<iostream>
using namespace std;
int main()
{

 int num,rev_num=0;
 cout<<"Enter a number:";
 cin>>num;
 while(num>0)
 {
  rev_num=rev_num*10+num%10;
  num=num/10;
 }
 cout<<rev_num<<endl;


 return 0;
}

Output:-

Enter a number:7890
0987

    HAPPY CODING.......

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