Sum of digits of a number

C++ program to find the sum of digits of a number.

Algorithm:-

Input=number
number1=0, sum=0;

while loop > 0

(a) number1 equal to remainder of number divide
    by 10
    number1=number%10;

(b) add sum and number1 to sum
    sum=sum+number1;

(c) divide number by 10
    number=number/10;
    
    print sum;
    
    exit;
    

Approach to solve:-

Input=259
number1=number%10=9
sum=sum+number1=9
number=number/10=25

number1=number%10=5
sum=sum+number1=14
number=number/10=2

number1=number%10=2
sum=sum+number1=16
number=number/10=0

Program:-

#include<iostream>
using namespace std;
int main(){
 int num,sum=0,num1=0;
 cout<<"ENTER THE NUMBER:";
 cin>>num;
 while(num>0)
 {
  num1=num%10;
  sum=sum+num1;
  num=num/10;
  
 }
 cout<<"SUM OF DIGITS:"<<sum;
 return 0;
}

Output:-

ENTER THE NUMBER:5990
SUM OF DIGITS:23

           KEEP CALM AND CODE...

if any query email me at:-sushank123456@gmail.com